The number of discons in a photon is equal to twice the frequency of the photon (2f).
The energy of a photon = hf Joules (Plancks constant x frequency). Therefore the energy of a single discon = hf/2f = h/2 Joules = 3.313034455 x 10ˆ-34 J.
Using e = mc^2, h/2 = mc^2, therefore the mass of a discon = h/2c^2 = 6.62606891x10ˆ-34 / (2 x 2997924582ˆ2 ) = 3.686247972 x 10^-51.
The mass of a discon = 3.686247972 x 10ˆ-51 Kg.
The least energetic photon consisting of 2 discons has a mass of 7.372495944 x 10ˆ-51 Kg and energy of 6.62606891x10ˆ-34 J.
Number of discons in an electron = electron mass / discon mass. = 9.1093897 x 10ˆ-31 Kg/3.686247972 x 10ˆ-51 Kg = 2.471182017 x 10ˆ20 discons.
Number of discons in a proton = proton mass / discon mass. = 1.6726231 x 10ˆ-27 Kg/3.686247972 x 10ˆ Kg = 4.537467671 x 10ˆ23 discons.
Number of discons in a neutron = neutron mass / discon mass. = 1.674929 x 10ˆ-27 Kg/3.686247972 x 10ˆ-51 Kg = 4.543723083 x 10ˆ23 discons. |